Prove that both the roots of the equation are real but they are equal only when .

For a quadratic equation, ax2 + bx + c = 0,


D = b2 – 4ac


If D > 0, roots are real.



x2 – (a + b)x + ab + x2 – (b + c)x + bc + x2 – (a + c)x + ac = 0


3x2 - 2(a + b + c)x + ab + bc + ac = 0


D = 4(a + b + c)2 – 12(ab + bc + ac)


D = a2 + b2 + c2 + 2ab + 2ac + 2bc – 3ab – 3bc – 3ac


D = 1/2 × (2a2 + 2b2 + 2c2 - 2ab – 2ac – 2bc)


D = 1/2 × ((a – b)2 + (b – c)2 + (c – a)2)


Thus, D is always greater than 0, and the roots are real


Now, when a = b = c,


D = 0, thus the roots are equal when a = b = c.


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