Determine two consecutive multiples of 3 whose product is 270.

Question

Philoid · Accepted Answer

Let the consecutive multiples of 3 be a, a + 3

⇒ a(a + 3) = 270

⇒ a² + 3a – 270 = 0

⇒ a² + 18a – 15a – 270 = 0

⇒ a(a + 18) -15(a + 18) = 0

⇒ (a – 15)(a + 18) = 0

⇒ a = 15

Numbers are 15, 18