Two numbers differ by 3 and their product is 504. Find the numbers.

Given, two numbers differ by 3.


Let one of the numbers be ‘a’.


Second number = a – 3


Also, their product is 504.


a(a – 3) = 504


a2 – 3a – 504 = 0


a2 – 24a + 21a – 504 = 0


a(a – 24) + 21(a – 24) = 0


(a + 21)(a – 24) = 0


a = -21, 24


Thus numbers are -21, -24 or 24, 21


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