A train travels 360 km at a uniform speed. If the speed had been 5 km / hr more, it would have taken 1 hour less for the same journey. Find the speed of the train.

Time = distance/speed


Given, train travels 360 km at a uniform speed. If the speed had been 5 km / hr more, it would have taken 1 hour less for the same journey.


Let the usual speed be ‘a’.



360 ×(a + 5 –a) = a2 + 5a


a2 + 5a – 1800 = 0


a2 + 45a – 40a – 1800 = 0


a(a + 45) – 40(a + 45) = 0


(a + 45)(a – 40) = 0


a = 40 km/hr


10