A train travels 360 km at a uniform speed. If the speed had been 5 km / hr more, it would have taken 1 hour less for the same journey. Find the speed of the train.
Time = distance/speed
Given, train travels 360 km at a uniform speed. If the speed had been 5 km / hr more, it would have taken 1 hour less for the same journey.
Let the usual speed be ‘a’.
⇒ 360 ×(a + 5 –a) = a2 + 5a
⇒ a2 + 5a – 1800 = 0
⇒ a2 + 45a – 40a – 1800 = 0
⇒ a(a + 45) – 40(a + 45) = 0
⇒ (a + 45)(a – 40) = 0
⇒ a = 40 km/hr