The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time. Find their present ages.

Let the present ages of the man and son be ‘a’ and ‘b’ respectively.


Given, sum of the ages of a man and his son is 45 years.


⇒ a + b = 45                    .............(1)


Ans, five years ago, the product of their ages was four times the man’s age at the time.


⇒ (a – 5)(b – 5) = 4(a – 5)


⇒ b – 5 = 4


⇒ b = 9 years


Thus, a = 45 – 9 = 36 years

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