The hypotenuse of a right triangle is 25 cm. The difference between the lengths of the other two sides of the triangle is 5 cm. Find the lengths of these sides.

Hypotenuse2 = perpendicular2 + base2


Given, hypotenuse of a right triangle is 25 cm. The difference between the lengths of the other two sides of the triangle is 5 cm


Let the base be ‘b’.


Perpendicular = b – 5


252 = b2 + (b – 5)2


625 = b2 + b2 + 25 – 10b


b2 – 5b – 300 = 0


b2 – 20b + 15b – 300 = 0


b(b – 20) + 15(b – 20) = 0


b = 20


Perpendicular = 20 – 5 = 15


Sides are 15 and 20


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