The general term of a sequence is given by .Is the sequence an A.P..? If so, find its 15th term and the common difference.

Put n = 1

A1= -4(1)2 + 15 = 11


Put n = 2


A2= -4(2)2 + 15 = -1


Put n = 3


A3= -4(3)2 + 15 = -21


Common difference, d1= a2 – a1 = -1 – 11 = -12


Common difference, d2= a3 – a2 = -21 + 1 = 20


Since, d1 ≠ d2


Therefore, it’s not an A.P.


6