The general term of a sequence is given by .Is the sequence an A.P..? If so, find its 15th term and the common difference.
Put n = 1
A1= -4(1)2 + 15 = 11
Put n = 2
A2= -4(2)2 + 15 = -1
Put n = 3
A3= -4(3)2 + 15 = -21
Common difference, d1= a2 – a1 = -1 – 11 = -12
Common difference, d2= a3 – a2 = -21 + 1 = 20
Since, d1 ≠ d2
Therefore, it’s not an A.P.