If an A.P. consists of n terms with first term a and nth term ls how that the sum of the mth term from the beginning and the mth term from the end is (a+l).
Given, a = a
Last term, l = l
We have to prove that the sum of the mth term from the beginning and mth term from the end is (a + 1)
Now, mth term from the beginning,
am(b) = a + (m – 1) l
= a + ml – l (i)
Again mth term from the end
am(e) = l – (m – 1)l
= l – ml + l = 2l – ml (ii)
By adding (i) and (ii), we get
a + ml – l + 2l – ml = a + l
Hence, proved