The 7th term of an A.P. is 32 and its 13th term is 62. Find the A.P.
a7 = 32
a + 6d = 32 (i)
a13 = a + 12d = 62 (ii)
By subtracting (i) from (ii), we get
6d = 30
d= 5
From (i), a = 32 – 6(5) = 2
We have to find A.P.
a1 = 2
a2 = a + d = 2 + 5 = 7
a3 = a + 2d = 2 + 2(5) = 12
a4 = a + 3d = 2 + 3(5) = 17
Hence, A.P. is 2, 7, 12, 17,…