Let, multiple of 4 lies between 10 and 250

12, 16, 20, 24,…248

We know, a_n = a + (n – 1)d

First term, a = 12

C0mmon difference, d = 16 – 12 = 4

Last term, a_n = 248

a_n = a+ (n – 1)d

248 = 12 + (n – 1) 4

248 = 12 + 4n – 4

4n = 248 – 12 + 4

4n = 240

n = 60

Hence, multiple of 4 lies between 10 and 250 is 60