Find the 10th term from the end of the A.P. .
a = 8, d = 2
Last term, an = 126
an = a + (n – 1) d
126 = 8 + (n – 1) 2
120 = 2n
n = 60
Now we have to find last 10th term, means = 60th – 9 = 51th term
Now, a51 = 8 + (51 – 1)2
= 8 + 50 * 2 = 8 + 100
= 108
Hence, 10th term from the last of given A.P. is 108