Given, a₄ + a₈ = 24 (i)

a₆ + a₁₀ = 44 (ii)

We know, a_n = a + (n – 1) d

4^th term, a₄ = a + 3d

6^th term, a₆ = a + 5d

8^th term, a₈ = a + 7d

10^th term, a₁₀ = a + 9d

Putting the value of a₄ and a₈ in (i), we get

a + 3d + a + 7d = 24

2a + 10d = 24 (iii)

Put the value of a₆ and a₁₀ in (ii), we get

a + 5d + a + 9d = 44

2a + 14d = 44 (iv)

By subtracting (iii) from (iv), we get

4d = 20

d = 5

Now putting value of d in (iii), we get

2a = 24 – 10(5)

a = -13

a₁ = -13

a₂ = a + d = -13 + 5 = - 8

a₃ = a + 2d = -13 + 10 = -3

Hence, the A.P. is -13, -8, -3,…