The 19th term of an A.P. is equal to three times its sixth term. If its 9th term is 19, find the A.P.
Given: a9 =19
a + 8d= 19 (i)
Acc. to question,
a19= 3a6 (ii)
a19=a + 18d
a6=a + 5d
Putting the value of a19 and a6 in (ii)
a + 18d =3(a +5d)
3d= 2a
3d=2(19 -8d) (from (i))
19d=38
d=2
Now, putting the value of d in (i)
a=19 -8(2) =3
a1 = a=3
a2 =a +d=3 +2=5
a3 =a +2d=3 + 2(2)=7
Hence, the A.P. is