If the seventh term of an A.P. is 1/9 and its ninth term is1/7, find its (63)rd term.
a7=
a +6d= (i)
a9 =
a +8d= (ii)
subtracting (i) from (ii), we get,
2d=
d=
a= –
=
a63= a + 62d
= +
=1