Find the value of x for which (8x+4), (6x-2), (2x+7) are in A.P.
We know that, if three numbers are a,b,c are in AP then, 2b = a + c
According to question, (8x+4), (6x-2), (2x+7) are in AP.
Hence,
2 (6x – 2) = 8x + 4 + 2x + 7
12x – 4 = 10x + 11
2x = 15
x = 15/2 = 7.5