Sum of the first 14 terms of an A.P. is 1505 and its first term is 10. Find its 25th term.
Given, a = 10
S14 = 1505
S14 = [2a + (n – 1) d]
1505 = [2(10) + (14 – 1) d]
1505 = 7 [20 + 13d]
215 = 20 + 13d
13d = 215 – 20
13d = 195
d = 15
Now, a25 = a + (n – 1) d
= 10 + (25 – 1) 15
= 10 + 24 * 15
= 10 + 360 = 370
Hence, value of 25th term is 370