Sum of the first 14 terms of an A.P. is 1505 and its first term is 10. Find its 25th term.

Given, a = 10

S14 = 1505


S14 = [2a + (n – 1) d]


1505 = [2(10) + (14 – 1) d]


1505 = 7 [20 + 13d]


215 = 20 + 13d


13d = 215 – 20


13d = 195


d = 15


Now, a25 = a + (n – 1) d


= 10 + (25 – 1) 15


= 10 + 24 * 15


= 10 + 360 = 370


Hence, value of 25th term is 370


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