If the sum of first n terms of an A.P. is (3n2 + 7n), then find its nth term. Hence write its 20th term.
Sn = (3n2 + 7n)
First term, a = S1 = [3(1)2 + 7(1)]
= [3 + 7] = 5
S2 = [3(2)2 + 7(2)]
a + a + d = [12 + 14]
5 + 5 + d = 13
d = 3
an = a + (n – 1)d
= 5 + (n – 1) 3
= 5 + 3n – 3
= 3n + 2
a20 = 3(20) + 2
= 60 + 2 = 62
Hence, it’s 20th term is 62