In Fig. 10.62, . The tangents to the circle at P and Q intersect at a point T. Prove that PQ and OT are right bisectors of each other.


AP and AQ are tangents to the circle with centre O, Ap perpendicular AQ


and AP=AQ=5 cm


We know that radius of a circle is perpendicular to the tangent at the point of contact OP perpendicular to AP and OQ perpendicular to AQ



but since adjacent side of OPAQ i.e AP and AQ are equal. Thus OPAQ is a square radius=OP=OQ=AP=5cm


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