Construct a triangle similar to a given 
such that each of its sides is 
of the corresponding sides of 
. It is given that BC = 6 cm, 
and 
.
Making the triangle:
● Draw a line segment BC = 6 cm.
● Make an angle of 50o at point B and an angle of 60o at point C (because 50 + 60 + 70 = 180).
● Join the lines from points B and C at point A.
● This gives the required triangle ABC.
Dividing the Base:
● Draw a ray BX at an acute angle from point B.
● Plot 4 points on BX so that BB1 = B1B2 = B2B3 = B3B4.
● Join B3 to C.
● Now, draw a line from B4 parallel to B3C so that it meets line BC at C’.
● Draw A’C’ || AC.
Triangle A’BC’ is the required triangle.
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