Construct a triangle similar to a given such that each of its sides is of the corresponding sides of . It is given that BC = 6 cm, and .

Making the triangle:

● Draw a line segment BC = 6 cm.


● Make an angle of 50o at point B and an angle of 60o at point C (because 50 + 60 + 70 = 180).


● Join the lines from points B and C at point A.


● This gives the required triangle ABC.



Dividing the Base:


● Draw a ray BX at an acute angle from point B.


● Plot 4 points on BX so that BB1 = B1B2 = B2B3 = B3B4.


● Join B3 to C.


● Now, draw a line from B4 parallel to B3C so that it meets line BC at C’.


● Draw A’C’ || AC.


Triangle A’BC’ is the required triangle.


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