Steps of construction

1. Construct a line segment AB of length 5 cm

2. From B constract an angle of 60o using compass and name it ABX

3. Construct a line EF parallel to line segment Ab at a height of 3 cm at a height of 3 cmsuch that it intersect BX at point C .Join AC

4. Construct CO perpendicular to AB . Cd is the altitude of the triangle ABC of height 3 cm

5. Construct AL making an acute angle with AB, on the side opposite to vertex C and mark 3 points(corresponding to the greater of 2 or 3) X1,X2 and X3 on AL Such that AX1=X1X2=X2X3

6. Join X2B and construct the line passing through X1 and parallel to X2B.Let this line intersect the extended line AB at R.

7.Now construct a line passing through R and parallel to BC which intersect the extended line AC at point Q