Draw a right triangle in which sides (other than the hypotenuse) are of lengths 8 cm and 6 cm. Then construct another triangle whose sides are 3/4 times the corresponding sides of the first triangle.

Steps of construction:

(a) Draw a right triangle in which sides (other than hypotenuse) are of lengths 8 cm and 6 cm.

(b) From any ray BX, making an acute angle with BC on the side opposite to the vertex A.

(c) Locate 4 points on BX such that

(d) Join B3C and draw a line through the point B4 , draw a line parallel to intersecting BC at the point C’.

(e) Draw a line through C’ parallel to the line CA to intersect BA at A’.

Then, A’BC’ is the required triangle

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