Construct a triangle PQR with sides QR = 7 cm, PQ = 6 cm and . Then construct another triangle whose sides are 3/5 of the corresponding sides of .

A triangle PQR whose sides are 3/5 of the corresponding sides of triangle ABC PQR can be drawn as follows


1. Draw a triangle PQR with side PQ= 7cm, QR = 6cm and angle PQR=60o


2. Draw a ray QX making an acute angle with QR on the opposite side of the vertex P.


3. Locate 5 points as 5 is greater in 3 and 5) Q1,Q2,Q3,Q4 and Q6. On line segment QX.


4. Join Q4R and Daw line through Q3, parallel to Q4R intersecting QR at R


5. Draw a line through R parallel to PR intersecting PQ at triangle P'QR' is the required triangle



Justification


The construction can be justified by providing



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