A tower stands vertically on the ground. From a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top the tower is 60°. What is the height of the tower?
Let the height of the tower = h (m)
In ∆ABC,
tan60° =
√3 =
h = 20√3 m
Therefore height of the tower is 20√3 m