A tower stands vertically on the ground. From a point on the ground, 20 m away from the foot of the tower, the angle of elevation of the top the tower is 60°. What is the height of the tower?

Let the height of the tower = h (m)



In ∆ABC,


tan60° =


√3 =


h = 20√3 m


Therefore height of the tower is 20√3 m


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