From the top of a building 15 m high the angle of elevation of the top of a tower is found to be 30°. From the bottom of the same building, the angle of elevation of the top of the tower is found to be 60°. Find the height of the tower and the distance between the tower and building.
Let the distance between tower and building = (m)
In ∆ABC,
tan 60° =
√3 =
=
√3 = h+15
h = √3-15 ------(1)
In ∆ABE,
tan 30° =
---------(2)
h = 3h-15 ⇒ 2h = 15
h = ⇒ 7.5 m.
Height of tower = 15+7.5 ⇒ 22.5 m.
⇒ 12.99 m.
Therefore distance between tower and building is 12.99 m.