A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on a hemisphere is immersed in the tub. If the radius of the hemisphere is immersed in the tub. If the radius of the hemi-sphere is 3.5 cm and height of the cone outside the hemisphere is 5 cm, find the volume of the water left into hr tub. 
Given radius of cylindrical tube(r) = 5 cm
Height of cylindrical tube (h) =9.8 cm
Volume of cylindrical =πr2h
V1 =π 52(9.8)
= 770 cm
Given of hemisphere = 3.5 cm
Height of cone (h) = 5 cm
Volume of hemisphere =
= 89.79 cm3
Volume of cone = 
= 64.14 cm3
Volume of cone + Volume of hemisphere (v2) = 89.79 + 64.14 = 154 cm3
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