A solid iron pole having cylindrical portion 110 cm high and of base diameter 12 cm is surmounted by a cone 9 cm high. Find the mass of the pole, given that the mass of 1 cm3 of iron is 8 gm.

Given radius of cylindrical part(r)= 12/2= 6 cm


Height of cylinder (h) = 110 cm


Length of cone (l)= 9 cm


Volume of cylinder=h


V1= π (6)2 110


Volume of cone=


V2=


=108π cm3


Volume of pole =v1 + v2


=+108


= 12785.14 108 cm3


Given mass of 1cm3 of iron = 8 gm


Mass of 1275.14 cm3 of iron = 12785.14 × 8


= 102281.12


=102.2 kg


Mass of pole for 12785.14 cm3 of iron is 102.2 kg


21