A cylindrical vessel with internal diameter 10 cm and height 10.5 cm is full of water. A solid cone of base diameter 7 cm and height 6 cm is completely immersed in water. Find the value of water (i) displaced out of the cylinder. (ii) left in the cylinder. 
Given internal radius (r1) = 10/2 = 5 cm
Height of cylindrical vessel (h) = 10.5 cm
Outer radius of cylindrical vessel (r2) = 7/2 = 3.5 cm
Length of cone (l) = 6 cm
(i)Volume of water displaced = Volume of cone
Volume of cone = 
= 
= 76.9 cm3
≈ 77 cm3
Volume of water displayed = 77 cm3
Volume of cylinder = πr2h
= π(5)210.5
= 824.6
≈ 825 
(ii)Volume of water left in cylinder = Volume of cylinder – Volume of cone
= 825 -77 = 748 cm3
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