In Fig. 16.57, from a cuboidal solid metallic block, of dimensions 15 cm × 10 cm × 5 cm, a cylindrical hole of diameter 7 cm is drilled out. Find the surface area of the remaining block.

Here, dimension of cuboid = 15 cm × 10 cm × 5 cm

Radius of cylindrical hole = cm


Surface area of the remaining block = surface area of cuboidal solid metallic block – 2 × base area of cylindrical hole


= 2(15 × 10 + 10 × 5 + 5 × 15) - 2 ×


= 583 cm2


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