A metallic right circular cone 20 cm high and whose vertical angle is 90° is cut into two parts at the middle point of its axis by a plane parallel to the base. If the frustum so obtained be drawn into a wire of diameter (1/16) cm, find the length of the wire
let ABC be the given cone.
Here, height of the metallic cone AO = 20cm
cone is cut nto two pieces at the middle point of the axis
hence, height of the frustum cone AD = 10cm
Since angle A is right angled, so ∠B and ∠C both = 45°
From triangle ADE,
⇒ r'=10cm
Similarly, from triangle AOB,
⇒ r''=20cm