What is the probability that an ordinary year has 53 Sundays?

Ordinary year has 365 days (52 weeks + 1 day)

That 1 day may be any day of the 7 days of a week


Therefore, total number of possible outcomes, n(S) = 7


And event of getting 53 Sunday is that 1 day is Sunday. Thus, n(E) = 1



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