It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?
Let E be the event of 2 students having the same birthday and _E’ be the event of not getting the same birthday
Given: P(E) = 0.992
We know that, P(E) + P(E’) = 1
∴ P(E’) = 1 – P(E)
= 1 – 0.992
= 0.008