Two dice, one blue and one grey, are thrown at the same time. Complete the following table:
Events: | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
Sum on two dice' | |||||||||||
Probability |
From the above table a student argues that there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability . Do you agree with this argument?
Total number of possible outcomes, n(S) = 36
Number of favorable outcomes = n(E)
We know that,
Sum of numbers on the two dice | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
n(E) | 1 | 2 | 3 | 4 | 5 | 6 | 5 | 4 | 3 | 2 | 1 |
Probability |