ABCD is a rhombus. If ACB = 40°, find ADB.



In rhombus ABCD


ACB = 40° given


ACB = CAD = 40° [Altermate interior angles are equal]


In ΔAOD


AOD = 90° [In rhombus diagonals bisect eact other at right angles]


AOD + CAD +ADB = 180° [Angle sum property of a triangle]


90° + 40° + ADB = 180°


ADB = 180°-130°


ADB = 50°


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