In a rectangle ABCD, prove that ΔACB ≅ΔCAD.
In ΔACB and ΔCAD
AB = CD [Opposite sides of a rectangle are equal]
BC = DA
AC = CA Common
ΔACB ≅ΔCAD (SSS Congurency)
5
In a rectangle ABCD, prove that ΔACB ≅ΔCAD.
In ΔACB and ΔCAD
AB = CD [Opposite sides of a rectangle are equal]
BC = DA
AC = CA Common
ΔACB ≅ΔCAD (SSS Congurency)