Find the measure of all the angles of a parallelogram, if one angle is 24° less than twice the smallest angle.

Question

Find the measure of all the angles of a parallelogram, if one angle is 24&#xB0; less than twice the smallest angle.

Philoid · Accepted Answer

Given,

Let the smallest angle = x^∘

Than the other angle = (2x – 24)°

So,

x^∘+x^∘+2x – 24 + 2x – 24 = 360^∘

6x = 360 + 48 = 408

Other angles = 2x – 24 = 2×68 – 24 = 136-24 = 112^∘

Angles are = 68^∘, 68^∘, 112^∘, 112^∘