Which of the following statements are true (T) and which are false (F)?

(i) In a parallelogram, the diagonals are equal.

(ii) In a parallelogram, the diagonals bisect each other.

(iii) In a parallelogram, the diagonals intersect each other at right angles.

(iv) In any quadrilateral, if a pair of opposite sides is equal, it is a parallelogram.

(v) If all the angles of a quadrilateral are equal, it is a parallelogram.

(vi) If three sides of a quadrilateral are equal, it is a parallelogram.

(vii) If three angles of a quadrilateral are equal, it is a parallelogram.

(viii)If all the sides of a quadrilateral are equal it is a parallelogram.

(i) False


Reason: Imagine a parallelogram and draw its diagonals. Now the areas of the two triangles on one of the bases is equal. But by Heron's formula, the areas are not equal and if the areas are not equal how can be the diagonals because area can only be equal if both the triangles have equal diagonals.


(ii) True


Proof:


Let’s take a parallelogram ABCD,


The diagonals AC and BD intersect each other at O,


AO = OC and BO = OD


In ΔAOB and ΔCOD,


We have


BAO = OCD (alternate interior angles)


AOB = CDO (alternate interior angles)


AB = DC (opposite sides)


ΔAOBΔCOD (by ASA)


AO = OC and DO = OB


(iii) False


According to the definition a parallelogram is a simple (non-self-intersecting) quadrilateral with two pairs of parallel sides. The opposite or facing sides of aparallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.


It turns out that a parallelogram has its diagonalsmeeting at right angles if and only if the parallelogram is a rhombus (all sides equal).


(iv) True


Reason: Let’s take ABCD is a quadrilateral,


Where AB = CD & AD = BC


We have to prove : ABCD is a parallelogram


Join AC, it’s a diagonal


In ΔABC and ΔCDA


AB = CD


BC = DA


AC = CA


ΔABCΔCDA


Hence,


BAC = DCA


For lines AB and CD with transversal AC,


BAC & DCA are alternate angles and are equal.


So, AB and CD lines are parallel.


BCA = DAC


For lines AD and BC with transversal AC,


BCA & DAC are alternate angles and are equal.


So, AD and BC lines are parallel.


Thus in ABCD,


Both pairs of opposite sides are parallel,


So, ABCD is a parallelgram.


(v) False


Reason: If all the angles of a quadrilateral are equal, then it’s a rectangle.


(vi) False


Reason:


As we know that the opposite or facing sides of aparallelogram are of equal length and the opposite angles of a parallelogram are of equal measure.


In case of square and rhombus all side are equal, but if three sides are equal then it doesn’t satisfied the property of parallelogram.


(vii) False


Reason:


Same reason as for the sides, it does not satisfied the property of a parallelogram.


(viii) True


Yes if all side of a parallelogram than it’s a square or rhombus.

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