In Fig. 14.97, BE⊥AC. AD is any line from A to BC intersecting BE in H, P, Q and R are respectively the mid points of AH, AB and BC. Prove that ∠PQR = 90°
Given,
In ΔABC,
Q, R are the mid points of AB and AC
QR ⎸⎸AC.. (i)
In ΔABH,
Q, P are the mid points of AB and AH respectively,
QP ⎸⎸BH
QP ⎸⎸BE.. (ii)
But AC⌃BE therefore from (i) and (ii)
QP⌃QR
∠PQR = 90∘