If ABCD is a rectangle with BAC=32°, find the measure of DBC.

Given,


ABCD is a rectangle



BAC = 32°


we know that diagonals of a rectangle bisects each other


Hence , AO = BO


And, DBA = BAC = 32° (angles infront of same sides)


DBC+DBA = 90°


DBC = 90° - 32° = 58°


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