In a parallelogram ABCD, the bisector of ∠A also bisects BC at X. Find AB : AD.
Given,
In parallelogram ABCD ,
Bisector of ∠A bisects BC at X
∵ AD││BC and AX cuts them so
∠DAX = ∠AXB (alternate angles)
∠DAX = ∠XAB (AX is bisector of ∠A)
∴∠AXB = ∠XAB
AB= BX (sides opposite of equal angles)
Now,
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