If one side of a parallelogram is 24° less than twice the smallest angle, then the measure of the largest angle of the parallelogram is

Let angles of parallelogram are A, B, C, D


Let smallest angle = A


Let largest angle = B


= B = 2A – 24°............(i)


A+B = 180° [adjacent angle of parallelogram]


So, A+2A -24° = 180°


= 3A = 180°+24° = 204°


=A =


= B = 2×68°-24° = 112°

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