If one side of a parallelogram is 24° less than twice the smallest angle, then the measure of the largest angle of the parallelogram is
Let angles of parallelogram are ∠A, ∠B, ∠C, ∠D
Let smallest angle = ∠A
Let largest angle = ∠B
= ∠B = 2∠A – 24°............(i)
∠A+∠B = 180° [adjacent angle of parallelogram]
So, ∠A+2∠A -24° = 180°
= 3∠A = 180°+24° = 204°
=∠A =
= ∠B = 2×68°-24° = 112°