ABCD is a parallelogram M is the mid-point of BD and BM bisects ∠B. Then, ∠AMB=
Given,
ABCD is a parallelogram,
M is mid point of BD
BM bisects ∠B
∵ ∠A+∠B = 180° [adjacent angles of parallelogram are supplementary]
In ∆AMB , ∠AMB+
= ∠AMB +
=∠AMB +
= ∠AMB = 180° - 90° = 90°