Given,

ABCD is a parallelogram

Diagonal AC bisects ∠BAD

∠BAC = 35°

∵∠A+∠B = 180° …………(i) [ angle sum property of quadrilateral]

∠A = 2∠BAC = 2×35° = 70°

Putting value of ∠A in equation (i)

= 70°+∠B = 180°

= ∠B = 180°-70° = 110°

∠ABC = 110°