Diagonals of a quadrilateral ABCD bisect each other. If ∠A =45°, then ∠B =
Given,
ABCD is a quadrilateral
∠A = 45° ,
∵ diagonals of quadrilateral bisects each other hence ABCD is a parallelogram,
= ∠A +∠B = 180°
=45°+∠B = 180°
=∠B = 180°- 45° = 135°