In ΔABC, E is the mid-point of median AD such that BE produced meets AC at F. If AC = 10.5 cm, then AF=

Question

In &#x394;ABC, E is the mid-point of median AD such that BE produced meets AC at F. If AC = 10.5 cm, then AF=

Philoid · Accepted Answer

Given,

In ∆ABC

E is mid point of median AD

AC = 10.5 cm

Draw DM││EF

∵ E is mid point of AD so F is mid point of AM

AF= FM ……………………(i)

In ∆BFC

EF││DM

SO, FM = MC ………………….(ii)

From(i) &(ii)

AF= MC……………..(iii)

AC = AF+MC+FM

= AC= AF+AF+AF From (i) (ii) &(iii)

AC = 3AF

AF =