In Fig. 15.82, ABC and ABD are two triangles on the base AB. If line segment CD is bisected by AB at O, Show that ar(Δ ABC) = ar(Δ ABD).
Given that,
CD bisected AB at O
To prove: Area () = Area (
)
Construction: CP perpendicular to AB and DQ perpendicular to AB
Proof: Area ( =
(AB * CP) (i)
Area ( =
(AB * DQ) (ii)
In , we have
∠CPO = ∠DQO (Each 90o)
Given that,
CO = DO
∠COP = ∠DOQ (Vertically opposite angle)
Then, by AAS congruence rule
Therefore,
CP = DQ (By c.p.c.t)
Thus,
Area ( = Area (
)
Hence, proved