A point D is taken on the side BC of a Δ ABC such that BD = 2DC. Prove that
ar(Δ ABD) = 2ar(Δ ADC)
Given that,
In Δ ABC,
We have
BD = 2DC
To prove: Area () = 2 Area (
)
Construction: Take a point E on BD such that, BE = ED
Proof: Since,
BE = ED and,
BD = 2DC
Then,
BE = ED = DC
Median of the triangle divides it into two equal triangles
Since,
AE and AD are the medians of ΔABD and AEC respectively
Therefore,
Area (ΔABD) = 2 Area (ΔAED) (i)
And,
Area (ΔADC) = Area (ΔAED) (ii)
Comparing (i) and (ii), we get
Area (ΔABD) = 2 Area (ΔADC)
Hence, proved