In square AB2CD, P and Q are mid-point of AB and CD respectively. If AB = 8 cm and PQ and BD intersect at O, then find area of ΔOPB.

Given: ABCD is a square

P and Q are the mid points of AB and CD respectively.


AB = 8cm


PQ and BD intersect at O


Now,


AP = BP = AB


AP = BP = * 8


= 4 cm


AB = AD = 8 cm


QP AD


Then,


AD = QP


So,


OP = AD


OP = * 8


= 4 cm


Now,


Area ( = * BP * PO


= * 4 * 4


= 8 cm2


Hence, Area ( is 8 cm2


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