In square AB2CD, P and Q are mid-point of AB and CD respectively. If AB = 8 cm and PQ and BD intersect at O, then find area of ΔOPB.
Given: ABCD is a square
P and Q are the mid points of AB and CD respectively.
AB = 8cm
PQ and BD intersect at O
Now,
AP = BP = AB
AP = BP = * 8
= 4 cm
AB = AD = 8 cm
QP ‖ AD
Then,
AD = QP
So,
OP = AD
OP = * 8
= 4 cm
Now,
Area ( =
* BP * PO
= * 4 * 4
= 8 cm2
Hence, Area ( is 8 cm2