ABCD is a parallelogram. P is the mid-point of AB. BD and CP intersect at Q such that CO:OP = 3:1. If Find the area of parallelogram ABCD.

Question

Philoid · Accepted Answer

Given that,

CQ: QP = 3: 1

Let,

CQ = 3x

PQ = x

Area ( = 10 cm²

We know that,

Area of triangle = * Base * Height

Area ( = * x * h

10 = * x * h

x * h = 20

Area ( = * 3x * h

= * 3 * 20

= 30 cm²

Now,

Area ( = * PB * H = 30 cm²

PB * H = 60 cm²

We have to find area of parallelogram

We know that,

Area of parallelogram = Base * Height

Area ( = AB * H

Area ( = 2 BP * H

Area (ABCD) = 2 (60)

Area (ABCD) = 120 cm²

Hence,

Area of parallelogram ABCD is 120 cm²