P is any point on base BC of ΔABC and D is the mid-point of BC. DE is drawn parallel to PA to meet AC at E. If then find area of ΔEPC.

Given that,

Area ( = 12 cm2


D is the mid-point of BC


So,


AD is the median of triangle ABC,


Area ( = Area ( = * Area (


Area ( = Area ( = * 12


= 6 cm2 (i)


We know that,


Area of triangle between the same parallel and on the same base


Area ( = Area (


Area ( + Area ( = Area ( + Area (


Area ( = Area ( (ii)


ME is the median of triangle ADC,


Area ( = Area ( + Area (


Area ( = Area ( + Area ( [From (ii)]


Area ( = Area (


6 cm2 = Area ( [From (i)]


Hence,


Area ( is 6 cm2.


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