If one side of a parallelogram is 24° less than twice the smallest angle, then the measure of the largest angle of the parallelogram is

Let the small angle be = x

Then the second angle = 2x - 24°


Since,


Opposite angles are equal the 4 angles will be x, 2x - 24° , x , 2x - 24°


So now by angle sum property:


x + 2x - 24° + x + 2x - 24° = 360°


6x - 48° = 360°


6x = 360° + 48°


6x = 408°


x =


x = 68°


Thus, the smallest angle is 68°


The second angle = 2 (68°) - 24°


= 112°

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